[Baypiggies] Fwd: manipulating lists question

[Martin Falatic]

Ah, genetics! Intriguing...

Do you need anything beyond the third elements of each list? Does the
third element always map 1:1 with the first, or could it vary? If so, what
then?

To refer to the simplified example, could you have this?
x = [['cat', 'NM123', 12], ['cat', 'NM234', 43], ['dog', 'NM56', 65]]

If so, what is the expected output?

 - Marty



On Thu, December 5, 2013 02:11, Vikram K wrote:
> i am having some difficulty in applying this to my actual problem
> although i love the dictionary method. Imagine the following three lists
> are the first, second and third elements of a larger list:
>
>>>> comp[6]
> ['6558', 'NM_001046.2', 'SLC12A2', '6037226', '2', 'chr5', '127502453',
> '127502454', 'het-ref', 'snp', 'A', 'T', 'A', '185', '113', '184', '112',
> 'VQHIGH', 'VQHIGH', '', '', '', '', '259974', '9', '6', '6', '15',
> '6558:NM_001046.2:SLC12A2:CDS:MISSENSE',
> '6558:NM_001046.2:SLC12A2:CDS:NO-CHANGE', 'PFAM:PF01490:Aa_trans', '', '',
>  '', '0.99', '2', '0.99', '0.998', '1.01', '1.000', '0.5', '0.46', '0.5',
>  '1', '18', '18', '19', 'ref-identical;onlyA', 'snp', '0.072', '-1',
> 'SQHIGH']
>
>
>>>> comp[7]
> ['1302', 'NM_080679.2', 'COL11A2', '6525172', '2', 'chr6', '33271374',
> '33271376', 'het-ref', 'del', 'GT', '', 'GT', '542', '542', '458', '458',
> 'VQHIGH', 'VQHIGH', '', '', '', '', '71150', '34', '106', '106', '140',
> '1302:NM_080679.2:COL11A2:TSS-UPSTREAM:UNKNOWN-INC',
> '1302:NM_080679.2:COL11A2:TSS-UPSTREAM:UNKNOWN-INC;1302:NM_080680.2:COL11A
> 2:TSS-UPSTREAM:UNKNOWN-INC;1302:NM_080681.2:COL11A2:TSS-UPSTREAM:UNKNOWN-
> INC;6257:NM_021976.3:RXRB:CDS:NO-CHANGE',
> '', '', '', '', '0.95', '2', '0.98', '0.998', '0.99', '1.000', '0.46',
> '0.42', '0.5', '0', '102', '102', '102', 'ref-identical;onlyA', 'del',
> '0.990', '6', 'SQHIGH']
>
>
>>>> comp[8]
> ['1302', 'NM_080680.2', 'COL11A2', '6525172', '2', 'chr6', '33271374',
> '33271376', 'het-ref', 'del', 'GT', '', 'GT', '542', '542', '458', '458',
> 'VQHIGH', 'VQHIGH', '', '', '', '', '71150', '34', '106', '106', '140',
> '1302:NM_080680.2:COL11A2:TSS-UPSTREAM:UNKNOWN-INC',
> '1302:NM_080679.2:COL11A2:TSS-UPSTREAM:UNKNOWN-INC;1302:NM_080680.2:COL11A
> 2:TSS-UPSTREAM:UNKNOWN-INC;1302:NM_080681.2:COL11A2:TSS-UPSTREAM:UNKNOWN-
> INC;6257:NM_021976.3:RXRB:CDS:NO-CHANGE',
> '', '', '', '', '0.95', '2', '0.98', '0.998', '0.99', '1.000', '0.46',
> '0.42', '0.5', '0', '102', '102', '102', 'ref-identical;onlyA', 'del',
> '0.990', '6', 'SQHIGH']
>
>>>>
>
> ------
> Can we apply the dictionary method to the problem where the key of the
> dictionary is the first element of the three smaller lists ('6558','1302',
>  '1302'). The second and third elements of the larger list (starting with
>  '1302') need to be collapsed into a single element, based on their
> second element ( 'NM_080679.2') and ('NM_080680.2') in a way similar to
> how we had tackled the toy problem:
>
> x = [['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog', 'NM56', 65]]
>
>
>
>
>
>
>
> On Thu, Dec 5, 2013 at 4:18 AM, Michiel Overtoom <motoom at xs4all.nl>
> wrote:
>
>
>>
>> On Dec 5, 2013, at 10:09, Vikram K wrote:
>>
>>
>>> another option could have been to obtain a dictionary like so: {'dog':
>>> ['NM56', 65], 'cat': ['NM123,NM234', 12]}
>>>
>>
>> Oh, in that case the code can become somewhat simpler:
>>
>>
>> x = [['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog', 'NM56', 65]]
>>
>> d = {} for key, label, quant in x: if key in d: d[key][0] += ", " + label
>> else:
>> d[key] = [label, quant]
>>
>> print d
>>
>>
>> I agree with Michael that the problem is somewhat underspecified, but
>> it's a starting point.
>>
>> Greetings,
>>
>>
>> --
>> "If you don't know, the thing to do is not to get scared, but to learn."
>> -
>> Ayn Rand
>>
>>
>>
>>
>>
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