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<div class="moz-cite-prefix">On 12/5/13 12:06 AM, Vikram K wrote:<br>
</div>
<blockquote
cite="mid:CABD-8FedNeRqHa94N1JMVH0NSML5WdjBeR3Q92AH=jB50aANQw@mail.gmail.com"
type="cite"><font class="Apple-style-span" face="arial,
sans-serif"><span class="Apple-style-span"
style="border-collapse:collapse">Any suggestions on what i
have to do to go from x to y?</span></font>
<div><font class="Apple-style-span" face="arial, sans-serif"><span
class="Apple-style-span" style="border-collapse:collapse"><br>
</span></font></div>
<div><font class="Apple-style-span" face="arial, sans-serif"><span
class="Apple-style-span" style="border-collapse:collapse">
<div>>>> x</div>
<div>[['cat', 'NM123', 12], ['cat', 'NM234', 12], ['dog',
'NM56', 65]]</div>
<div>>>> y = [['cat','NM123, NM234', 12], ['dog',
'NM56', 65]]</div>
</span></font></div>
</blockquote>
<font face="arial, sans-serif"><br>
How about this:<br>
<br>
</font><tt> from itertools import groupby</tt><tt><br>
from operator import itemgetter<br>
</tt><tt> key = itemgetter(0, 2)</tt><tt><br>
</tt><tt> y = [[k[0], ', '.join(h[1] for h in g), k[1]]</tt><br>
<tt> </tt><tt>for k, g in groupby(sorted(x,
key=key), key)]</tt><br>
<br>
Monte<br>
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