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<br><p>Counting the Colors of RGB-Image, <br></p><p id="__paragraph__1326641755000" style="">nameit im0<span style=""> with im0.shape = 2500,3500,3</span><span></span></p><p id="__paragraph__1326641783000" style="">with this code:<span></span></p><p id="__paragraph__1326641841000" style=""><br><span style=""></span></p><p style=""><span style="">tab0 = zeros( (256,256,256) , dtype=int)<br></span></p><p id="__paragraph__1326641821000" style="">tt = im0.view()<span></span></p><p id="__paragraph__1326641969000" style=""><span style="">tt.shape = -1,3</span><span></span></p><p style=""><span style="">for r,g,b in tt:</span><span></span></p><p id="__paragraph__1326642035000" style=""><span style=""> tab0[r,g,b] += 1</span><span></span></p><p id="__paragraph__1326642060000" style=""><br><span style=""></span></p><p style="">Question:<span></span></p><p style=""><br><span style=""></span></p><p style=""><span style="">Is there a faster way in numpy to get this result?</span><span></span></p><p id="__paragraph__1326642105000" style=""><br></p><p style=""> <br><span style=""></span></p><p style=""><span style="">MfG elodw<br></span></p><p style=""><span style=""><br></span></p><p style=""><span style=""><br></span></p><br><basefont size="2" face="Verdana"></body></html>