<HTML><BODY>Thanks<br><br>But I could find for Win64 bit windows????<br>Second question: Did you mean that I have to put lens limits of those number??? <br><br><br>Пятница, 21 декабря 2012, 15:45 UTC от Pauli Virtanen <pav@iki.fi>:<br>
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<div id="style_13561047730000000086_BODY">Hi,<br><br>Your code tries to to evaluate<br><br> z = 1263309.3633394379 + 101064.74910119522j<br> jv(536, z)<br> # -> (inf+inf*j)<br><br>In reality, this number is not infinite, but<br><br> jv(536, z) == -2.3955170861527422e+43888 + 9.6910119847300024e+43887<br><br>These numbers (~ 10^43888) are too large for the floating point<br>numbers that computers use (maximum ~ 10^308). This is why you get<br>infinities and NaNs in the result. The same is true for the spherical<br>Bessel functions.<br><br>You will not be able to do this calculation using any software<br>that uses only floating point numbers (Scipy, Matlab, ...).<br><br>You need to use analytical properties of your problem to<br>get rid of such large numbers. Alternatively, you can use arbitrary<br>precision numbers. Python has libraries for that:<br><br><a href="http://code.google.com/p/mpmath/" target="_blank">http://code.google.com/p/mpmath/</a><br><br><br>By the way, the proper place for this discussion is the following<br>mailing list:<br><br><a href="http://mail.scipy.org/mailman/listinfo/scipy-user" target="_blank">http://mail.scipy.org/mailman/listinfo/scipy-user</a><br><br>-- <br>Pauli Virtanen<br><br><br>_______________________________________________<br>NumPy-Discussion mailing list<br><a href="sentmsg?compose&To=NumPy%2dDiscussion@scipy.org">NumPy-Discussion@scipy.org</a><br><a href="http://mail.scipy.org/mailman/listinfo/numpy-discussion" target="_blank">http://mail.scipy.org/mailman/listinfo/numpy-discussion</a><br></div>
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