# [issue2706] datetime: define division timedelta/timedelta

STINNER Victor report at bugs.python.org
Fri Nov 14 18:51:30 CET 2008

```STINNER Victor <victor.stinner at haypocalc.com> added the comment:

Why not also implementing divmod()? It's useful to split a timedelta
into, for example, (hours, minutes, seconds):

def formatTimedelta(delta):
"""
>>> formatTimedelta(timedelta(hours=1, minutes=24, seconds=19))
'1h 24min 19sec'
"""
hours, minutes = divmodTimedelta(delta, timedelta(hours=1))
minutes, seconds = divmodTimedelta(minutes, timedelta(minutes=1))
seconds, fraction = divmodTimedelta(seconds, timedelta(seconds=1))
return "{0}h {1}min {2}sec".format(hours, minutes, seconds)

My implementation gives divmod(timedelta, timedelta) -> (long,
timedelta). It's a little bit strange to get two different types in
the result. The second return value is the remainder. My example works
in the reverse order of the classical code:

def formatSeconds(seconds):
"""
>>> formatTimedelta(1*3600 + 24*60 + 19)
'1h 24min 19sec'
"""
minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)
return "{0}h {1}min {2}sec".format(hours, minutes, seconds)

- based on datetime_datetime_division_dupcode.patch
- create divmod() operation on (timedelta, timedelta)
- add unit tests for the division (floor and true division) and
divmod
- update the documentation for the true division and divmod

----------
nosy: +haypo