[Python-Dev] redefining is
nas-python at python.ca
Fri Mar 19 17:28:39 EST 2004
On Fri, Mar 19, 2004 at 03:33:41PM -0500, Andrew Koenig wrote:
> It certainly doesn't *require* a builtin operator. I do think,
> however, that the proposed comparison is more useful than "is" in
> most contexts in which programmers use "is" today.
Are you saying that most instances of "is" in current Python code
are incorrect? If not, what do you mean by more useful?
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