[Python-ideas] Tweaking closures and lexical scoping to include the function being defined

[Greg Ewing]

Nick Coghlan wrote:

> Now, the use of 'nonlocal' in the inner function has *changed the
> lifecycle* of x. It is now a nonlocal variable - it survives beyond
> the execution of the function that defines it.

Yes, but that's just a logical consequence of the fact
that it's *visible* from the inner function, together
with the fact that Python never throws anything away
while it's still accessible. Visibility is still the
primary concept attached to 'nonlocal'.

-- 
Greg