Python 2.2b1 (#25, Oct 19 2001, 11:44:52) [MSC 32 bit (Intel)] on win32
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>>> import re
>>> s="""a\nb\n1"""
>>> re.findall("[^\n]+?\d", s)
['a\nb\n1']
Didn't get a response posting this on sourceforge.
Now I'm off on vaction for a week.
--Darrell Gallion