Howto: extract a 'column' from a list of lists into a new list?
Lulu of the Lotus-Eaters
mertz at gnosis.cx
Tue Jul 1 09:30:28 CEST 2003
"Greg Brunet" <gregbrunet at NOSPAMsempersoft.com> wrote previously:
|[('STOCKNO', 'C', 8, 0), ('DACC', 'C', 5, 0), ('DEALERACCE', 'C', 30,
|0), ('D-ACCRTL', 'C', 9, 0), ('D-ACCCST', 'C', 9, 0)]
NAME,TYPE,LEN,DEC = range(4)
names = [row[NAME] for row in tbl.Fields()]
Keeping medicines from the bloodstreams of the sick; food from the bellies
of the hungry; books from the hands of the uneducated; technology from the
underdeveloped; and putting advocates of freedom in prisons. Intellectual
property is to the 21st century what the slave trade was to the 16th.
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