List operator overloading snag

[Peter Otten]

Steven Brent wrote:

>>>> print S1 or S2
> Set: ['s', 'p', 'a', 'm'] # custom __repr__ used but still default
>                           # __or__ behavior, returns first true operand
> 
>>>> print S1.__or__(S2)
> using Set.__or__
> Set: ['s', 'p', 'a', 'm', 'c', 't'] # now all the custom behaviors

Try S1 | S2 instead, __or__() somewhat misleadingly implements the | aka
"bitwise or" operator.

Peter