knowing a file's own name
Scott Frankel
leknarf at pacbell.net
Mon Nov 29 18:53:50 EST 2004
Thanks for the responses!
I'd forgotten about using the sys module:
import sys
filename = sys.argv[0]
Using "__file__" also works.
Thanks
Scott
On Nov 29, 2004, at 9:37 AM, Scott Frankel wrote:
>
> I'm looking for a way to identify a filename remotely. Put
> differently,
> is there a way a file can get its own name from its globals()?
>
> doit.py calls exec() on a second py script, tpairs.py, to obtain a
> dict of the
> globals in tpairs.py. How can I add the filename, "tpairs.py," to the
> resulting dict?
> i.e.:
>
> # - - - - - - - - - - - - - - - -
> # -- tpairs.py
> # - - - - - - - - - - - - - - - -
> this = "this"
> that = "that"
> gdict = globals()
>
> # - - - - - - - - - - - - - - - -
> # -- doit.py
> # - - - - - - - - - - - - - - - -
> #!/usr/bin/env python
>
> theFile = "./tpairs.py"
> theDict = {}
> execfile(theFile, theDict)
>
> # somehow add theFile to gdict, i.e.:
> # gdict['theFile'] = theFile
>
>
> Thanks in advance!
> Scott
>
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