datetime.time() class - How to pass it a time string?
gagsl-py2 at yahoo.com.ar
Wed Jul 25 03:45:51 CEST 2007
En Tue, 24 Jul 2007 14:37:20 -0300, Miles <semanticist at gmail.com> escribió:
> On 7/24/07, Robert Dailey wrote:
>> I have a string in the following format:
>> I would like to pass this string into the datetime.time() class and
>> have it parse the string and use the values. However, the __init__()
>> method only takes integers (which means I'd be forced to parse the
>> string myself). Does anyone know of a way I can make it use the
>> string? Thanks.
> timestr = "00:00:25.886411"
> timesep = re.compile('[:.]')
> datetime.time(*[int(i) for i in timesep.split(timestr)])
That's OK if one can always guarantee the 6 digits after the decimal
point; else a bit more work is required:
py> timestr = "00:00:25.886"
py> h, m, s = timestr.split(":")
py> if '.' in s:
... s, us = s.split('.')
... us = us[:6].ljust(6, '0')
... us = 0
py> datetime.time(int(h), int(m), int(s), int(us))
datetime.time(0, 0, 25, 886000)
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