a regual expression problem
roy at panix.com
Sun Nov 30 15:59:11 CET 2008
<8cb784fc-809b-444e-b8a7-e4129a4a58ee at w24g2000prd.googlegroups.com>,
lookon <areyoulookon at gmail.com> wrote:
> I have a url of image, and I want to get the filename and extension of
> the image. How to write in python?
> for example, the url is http://a.b.com/aaa.jpg?version=1.1
> how can I get aaa and jpg by python?
Despite the subject line, this is *not* a regex problem. The right tool is
Python's built-in urlparse module, which understands the full syntax of
urls. Trying to roll your own from scratch using split() or regex is the
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