Float precision and float equality
sturlamolden at yahoo.no
Sun Dec 6 22:48:24 CET 2009
On 6 Des, 21:52, r0g <aioe.... at technicalbloke.com> wrote:
> > .> Right. Using abs(x-y) < eps is the way to go.
> > .>
> > .> Raymond
> > This only works when abs(x) and abs(y) are larger that eps, but not
> > too much larger.
> Okay, I'm confused now... I thought them being larger was entirely the
Yes. dbd got it wrong. If both a smaller than eps, the absolute
difference is smaller than eps, so they are considered equal.
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