# Loop problem while generating a new value with random.randint()

Jean-Michel Pichavant jeanmichel at sequans.com
Mon Feb 15 17:17:39 CET 2010

```Paulo Repreza wrote:
> Greetings,
>
> I'm having problems with a little script that I'm trying to finish, I
> don't know if I'm in the right track but I know somebody is going to
> help me.
>
> The script:
>
> # Import modules random for function randint
>
> import random
>
> # Generating a constant.
>
> var = 65
>
> # Generating a random number.
> ranum = random.randint(1,100)
>
> #Creating while loop. Stops until var == ranum
> while var != ranum:
>     if var == ranum:
>         print var, 'equals to:', ranum
>     else:
>         print var, 'does not equal to:', ranum
>
> ########## End of Script ###########
>
>
> What I'm trying to do is to print the new value that ranum generates
> if the condition is not met. So far if you run the script it prints
> the same value over and over again, making in an infinite loop. What
> can I do in order to print out the new value generated every time the
> condition is not met?
>
> Thanks!
>
> Paulo Repreza
in your script you generate the random number only once, no wonder it
keep being the same value over & over.

# Initialize ranum with a random number
ranum = random.randint(1,100)

#Creating while loop. Stops until var == ranum
while var != ranum:
if var == ranum:
print var, 'equals to:', ranum
else:
print var, 'does not equal to:', ranum
ranum = random.randint(1,100) # generate a new number, that's the