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<blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid"><br><br>Hijacking Brian's response since my newsserver never god Ben's original<br>request...:<br><br>I would program this at a reasonably high abstraction level, based on
<br>sets -- since you say order doesn't matter, sets are more appropriate<br>than lists anyway. For example:<br><br>def two_cont_in_common(x, y):<br> common = set(x).intersection(y)<br> return bool(common.intersection
(z+1 for z in common))<br><br>i.e., given two lists or whatever, first build the set of all elements<br>they have in common, then check if that set contains two continuous<br>elements. Then, as Brian suggests, you can use this dyadic function on
<br>a reference list and as many others as you wish:<br><br>def bens_task(reference, others):<br> return [two_cont_in_common(alist, reference) for alist in others]<br><br>The call bens_task(lisA, lisB, lisC, lisD) will give you essentially
<br>what you require, except it uses True and False rather than 1 and 0; if<br>you need to fix this last issue, you can add an int(...) call around<br>these booleans in either of the functions in question.<br><br><br>Alex
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<div>I got invalid syntax error when i run Alex's code. do not know why.</div><br> </div>