<font face="trebuchet ms,sans-serif" style="color:rgb(34,34,34);font-size:13.333333969116211px;background-color:rgb(255,255,255)">Maybe</font><div style="color:rgb(34,34,34);font-family:arial,sans-serif;font-size:13.333333969116211px;background-color:rgb(255,255,255)">
<font face="trebuchet ms,sans-serif"><br></font></div><div style="color:rgb(34,34,34);font-family:arial,sans-serif;font-size:13.333333969116211px;background-color:rgb(255,255,255)"><font face="trebuchet ms,sans-serif">l = filter(a, lambda v: v == a[-1]) </font><div>
<font face="trebuchet ms,sans-serif">sorted(a[:-len(l)]) + l</font></div><div><br></div><div><font face="trebuchet ms, sans-serif">?</font></div></div><br><div class="gmail_quote">On Fri, Sep 28, 2012 at 4:51 PM, dave <span dir="ltr"><<a href="mailto:davidreynon@gmail.com" target="_blank">davidreynon@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">more clearer, this is a more realistic use case:<br>
<br>
['awefawef', 'awefawfsf', 'awefsdf', 'zzzzzzzzzzzzzz', 'zzzzzzzzzzzzzz', 'zzzzzzzzzzzzzz']<br>
<br>
and the quantity of ''zzzzzzzzzzzzzz'' would be dynamic.<br>
<div class="im HOEnZb"><br>
On Friday, September 28, 2012 4:46:15 PM UTC-7, Ian wrote:<br>
<br>
><br>
> > a = ['a', 'b', x]<br>
><br>
> ><br>
><br>
> > b = sorted(a)<br>
><br>
> ><br>
><br>
> > What does x need to be to always be last on an ascending sort no matter what 'a' and 'b' are.... within reason... I am expecting 'a' and 'b' will be not longer than 10 char's long.... I tried making x = 'zzzzzzzzzzzzzzzz' and believe it or not, this appears FIRST on the sort!!!<br>
><br>
><br>
><br>
</div><div class="HOEnZb"><div class="h5">> It appears last when I run the code.<br>
><br>
><br>
><br>
> To answer your question, though, if you want to force x to be last,<br>
><br>
> then I suggest removing it from the list and then appending it to the<br>
><br>
> end.<br>
--<br>
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</div></div></blockquote></div><br>