[python-win32] Vista and listening sockets

[le dahut]

Hello,

When launching an app that opens a socket, windows Vista complains that 
I have to accept it before it is launched and then that the firewall 
accepts the opening of the port.

Is there a way to register my app to be launched by users without UAC 
warning ?

Is there a way to open the port on the firewall inside the program or 
its installer ?

Thanks.