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<TITLE>RE: [Tkinter-discuss] calling toplevel creating function</TITLE>
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<P><FONT SIZE=2>Hi Michael,<BR>
<BR>
my code is below. actually the problem that I explained in my previous mail can be solved by using newkey() instead of self.newkey() toplevel definition.(but still could not understand what is the reason of the error message) however, still I could not reach my aim. As you will see below, I could not assign self.userkey which is gotten from the user on toplevel window, to the userdefinedkey[] array. the aim is, at first click of a key should result with a toplevel window that gets the key parameter from the user. the other press of the same key should result by calling a different function with the parameter taken. there are more than one such a key on my GUI. I hope, I can explain my aim and problems:) thanks from now...<BR>
<BR>
<BR>
<BR>
from Tkinter import *<BR>
<BR>
root = Tk()<BR>
<BR>
class myentryclass:<BR>
def __init__(self, parent):<BR>
self.myParent = parent<BR>
self.myParent.focus_set()<BR>
<BR>
self.mycontainer = Frame(parent, borderwidth=0)<BR>
self.mycontainer.pack()<BR>
<BR>
<BR>
userdefinedkeys=[]<BR>
for i in range (2):<BR>
userdefinedkeys.append('')<BR>
<BR>
button_name=self.userdefinedkeys[0]<BR>
button_number=1<BR>
self.key1=Button(self.mycontainer,<BR>
command=lambda<BR>
arg1=button_name, arg2=button_number:<BR>
self.Button_Press(arg1, arg2)<BR>
)<BR>
self.key1.configure(text="key1")<BR>
self.key1.grid(row=3, column=0)<BR>
<BR>
button_name=self.userdefinedkeys[1]<BR>
button_number=2<BR>
self.key2=Button(self.mycontainer,<BR>
command=lambda<BR>
arg1=button_name, arg2=button_number:<BR>
self.Button_Press(arg1, arg2)<BR>
)<BR>
self.key2.configure(text="key2")<BR>
self.key2.grid(row=3, column=1)<BR>
<BR>
<BR>
def Button_Press(self, arg1, arg2):<BR>
if arg2==1:<BR>
if arg1=='':<BR>
self.newkey()<BR>
self.userdefinedkeys[0]=self.userkey<BR>
else:<BR>
print self.userdefinedkeys[0]<BR>
if arg2==2:<BR>
if arg1=='':<BR>
self.newkey()<BR>
self.userdefinedkeys[1]=self.userkey<BR>
else:<BR>
print self.userdefinedkeys[1]<BR>
<BR>
else:<BR>
pass<BR>
<BR>
def newkey(self):<BR>
newkey=Toplevel()<BR>
newkey.title('Define New Key')<BR>
newkey.geometry('250x140+500+300')<BR>
<BR>
self.keydef = Label(newkey, text="Key Name:")<BR>
self.keydef.place(x=10, y=10)<BR>
self.keyname = Entry(newkey)<BR>
self.keyname.focus_set()<BR>
self.keyname.place(x=90, y=10)<BR>
confirm = Button(newkey, text="OK", width=15, command=self.getkeyname)<BR>
confirm.place(x=67, y=85)<BR>
<BR>
def getkeyname(self):<BR>
self.userkey=self.keyname.get()<BR>
## self.newkey.destroy()<BR>
print self.userkey<BR>
return self.userkey <BR>
<BR>
<BR>
def sendcommand(self, arg1):<BR>
print arg1<BR>
<BR>
<BR>
mylittlentry = myentryclass(root)<BR>
root.mainloop()<BR>
<BR>
<BR>
<BR>
-----Original Message-----<BR>
From: tkinter-discuss-bounces@python.org on behalf of Michael Lange<BR>
Sent: Tue 5/30/2006 12:30 AM<BR>
To: tkinter-discuss@python.org<BR>
Subject: Re: [Tkinter-discuss] calling toplevel creating function<BR>
<BR>
On Mon, 29 May 2006 14:54:28 +0300<BR>
"Ilknur Ozturk" <Ilknur.Ozturk@cabot.com.tr> wrote:<BR>
<BR>
> Hi all,<BR>
><BR>
> <BR>
><BR>
> I have a problem with toplevel window. It is created within a function<BR>
> and I am calling that function by button press. I have created 4 buttons<BR>
> that call same toplevel creating function. For the first call, there is<BR>
> no problem. The toplevel window is created and get the arguments. But<BR>
> the other call for that function results with an error message like;<BR>
><BR>
> <BR>
><BR>
> "Toplevel instance has no __call__ method"<BR>
><BR>
<BR>
Hi Ilknur,<BR>
<BR>
can you show us the code and a complete traceback, otherwise we can only guess.<BR>
The error message you described can be reproduced by the folllowing code snippet:<BR>
<BR>
>>> t=Toplevel()<BR>
>>> t()<BR>
Traceback (most recent call last):<BR>
File "<stdin>", line 1, in ?<BR>
AttributeError: Toplevel instance has no __call__ method<BR>
>>><BR>
<BR>
so maybe the problem is the name you give to your Toplevel instance.<BR>
<BR>
Michael<BR>
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