[Tutor] a simple password program
Karl Pflästerer
sigurd at 12move.de
Thu Mar 11 16:48:43 EST 2004
On 11 Mar 2004, Nick Noda <- simple_twist at adelphia.net wrote:
> while password != "nabbers":
> if count < 3:
> password = raw_input("Password:")
> count = count + 1
> else:
> print "Too complicated, huh?"
> print "Welcome inside."
> i can get it to say "Welcome inside." if the pass is correct, but if the
> pass is guessed wrong three times it just keeps looping "Too complicated,
> huh?" i was wondering if it is supposed to do that or if there is a way
> that i can get it to say it once then quit. any help i would jump up and
> down for.
Think what happens if after the third pass the password is still wrong:
The loop looks in the condition: password != "nabbers!" which is true,
so the loop starts a new cycle; count is bigger than three so it jumps
directly to the else part, prints its message and starts a new cycle ...
So you have to find a way to break the loop unconditionally: if you only
wanted to stop the loop `break' would be right, but you also want to
stop the programm; for that you could use a method from the sys module:
sys.exit().
You could write:
import sys
count = 0
password = ""
while password != "nabbers":
if count < 3:
password = raw_input("Password: ")
count += 1
else:
print "Too complicated, huh?"
sys.exit()
print "Welcome inside."
Karl
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