From lysdexia at crackrabbit.com Fri Oct 1 01:32:05 2004
From: lysdexia at crackrabbit.com (Douglas N. Shawhan)
Date: Fri Oct 1 01:32:56 2004
Subject: [Tutor] Is there a prettier way to do this?
Message-ID: <415C9775.7040306@crackrabbit.com>
I am trying to
sort through a list of items,
find items that contain the same string fragments and
report yea or nay
The way I am doing it below (setting a value of 1 and multiplying it by
0 if any of the iterations come up negative) seems to be the easiest for
my skull, but I have found over and over that there is usually a more
pythonic way of doing things, no matter what I come up with! :-)
-------------------------snip-------------------------------
import string
DB = {"hi":"one, two", "ho":"two, three", "he":"three, one"}
search_str='three, one'
search_list=string.split(search_str, ",")
items = DB.keys()
items.sort()
search_group=[]
for each in items:
search_group.append(DB[each])
for each in search_group:
count = 1
for item in search_list:
if string.find(each, item) == -1:
count = count * 0
else:
count = count * 1
if count == 0:
print 'not found'
else:
print each
From kent_johnson at skillsoft.com Fri Oct 1 02:35:01 2004
From: kent_johnson at skillsoft.com (Kent Johnson)
Date: Fri Oct 1 02:35:07 2004
Subject: [Tutor] Is there a prettier way to do this?
In-Reply-To: <415C9775.7040306@crackrabbit.com>
References: <415C9775.7040306@crackrabbit.com>
Message-ID: <6.1.0.6.0.20040930203315.02a47ce0@mail4.skillsoft.com>
Here's my take on it, with comments in-line.
Kent
# You don't need the string module, use the string methods instead
DB = {"hi":"one, two", "ho":"two, three", "he":"three, one"}
search_str='three, one'
search_list=search_str.split(",")
# search_list is now ['three', ' one']
# Note the space before 'one' - this may not be what you want.
# You could split on ', ' if you always have the space, or use a regex
split, or
# omit the space in the original data...
# Personally I like to get the key, value pairs if I am going to need both
# Is there a reason why you are using a dict? for this snippet a list of
pairs would
# make more sense
items = DB.items()
items.sort()
# A list comprehension makes this very concise
search_group = [value for key, value in items]
# In Python 2.4 you will be able to do this in one line:
# search_group = [value for key, value in DB.items().sorted()]
# Usually a loop with a break is a better way to code something like this
for each in search_group:
for item in search_list:
if item not in each: # Since Python 2.3 you can do a find like this
# At this point we know we're not going to find them all so we
can stop
print 'not found'
break
else:
# This will only be run if the loop exits without a break
print each
At 06:32 PM 9/30/2004 -0500, Douglas N. Shawhan wrote:
>I am trying to
>sort through a list of items,
>find items that contain the same string fragments and
>report yea or nay
>
>The way I am doing it below (setting a value of 1 and multiplying it by 0
>if any of the iterations come up negative) seems to be the easiest for my
>skull, but I have found over and over that there is usually a more
>pythonic way of doing things, no matter what I come up with! :-)
>
>-------------------------snip-------------------------------
>import string
>
>DB = {"hi":"one, two", "ho":"two, three", "he":"three, one"}
>
>search_str='three, one'
>search_list=string.split(search_str, ",")
>
>items = DB.keys()
>items.sort()
>search_group=[]
>
>for each in items:
> search_group.append(DB[each])
>
>for each in search_group:
> count = 1
> for item in search_list:
> if string.find(each, item) == -1:
> count = count * 0
> else:
> count = count * 1
> if count == 0:
> print 'not found'
> else:
> print each
>
>_______________________________________________
>Tutor maillist - Tutor@python.org
>http://mail.python.org/mailman/listinfo/tutor
From lysdexia at crackrabbit.com Fri Oct 1 05:53:39 2004
From: lysdexia at crackrabbit.com (Douglas N. Shawhan)
Date: Fri Oct 1 05:54:33 2004
Subject: [Tutor] Is there a prettier way to do this?
In-Reply-To: <6.1.0.6.0.20040930203315.02a47ce0@mail4.skillsoft.com>
References: <415C9775.7040306@crackrabbit.com>
<6.1.0.6.0.20040930203315.02a47ce0@mail4.skillsoft.com>
Message-ID: <415CD4C3.2050009@crackrabbit.com>
Kent Johnson wrote:
>
> # You don't need the string module, use the string methods instead
>
> search_list=search_str.split(",")
Yes! Very good.
>
> # search_list is now ['three', ' one']
> # Note the space before 'one' - this may not be what you want.
> # You could split on ', ' if you always have the space, or use a regex
> split, or
> # omit the space in the original data...
Good advice!
>
> # Personally I like to get the key, value pairs if I am going to need
> both
> # Is there a reason why you are using a dict? for this snippet a list
> of pairs would
> # make more sense
>
> items = DB.items()
> items.sort()
Yes, this makes more sense and removes a step.
The problem is: I think I was unclear stating what the loop is supposed
to do!
I need to find *more than one* string fragment per string.
Say I need to verify the existence of the sequences "joe", "bill" and
"leon" in a string - but the next time I may need only find "joe" and
"bill", which is why I went with the 0, 1 scheme.
It may be better stated as: "How do I find arbitrary numbers of
substrings in arbitrary order in a string pythonically?"
From s4046441 at student.uq.edu.au Fri Oct 1 07:38:49 2004
From: s4046441 at student.uq.edu.au (Ms Soo Chong)
Date: Fri Oct 1 07:38:57 2004
Subject: [Tutor] How can I code to get more than ONE value from checkbox?
Message-ID: <6ac8f66b26df.6b26df6ac8f6@uq.edu.au>
Hi,
I'm trying to code a python script (with HTML) to get values from a
html form that consists of about 10 checkbox and a textbox where user
have to key in a value to perform a search.
>From Lee Harr and Danny, I learned that I have to use the following method:
###
qtype = data.getfirst('qtype') ---- checkbox name
qtext = data.getfirst('qtext', '') ---- textbox name
###
but I don't really know how to do it. Should I use qtype =
data.getlist('qtype') to get the value from the checkbox and how to?
Currently, my method required me to type in every possible combination
of the checkbox and I know that this is wrong. I wanna to include
%(qtype) in my query statement so that the script will look for the
value that contain qtype everytime a form is processs but the way I'm
doing now is wrong.
query = "select %(qtype)s from shot_descriptions where
shot_number=%(qtext)s", qtype, qtext
Thus, can someone help me on this.
Thank you for any help.
Shufen
-------------- next part --------------
#!/usr/bin/env python
#Created on: 30/09/04
#Help from Lee Harr and Danny Yoo - Python Tutor
import sys, os
import cgi
import cgitb; cgitb.enable()
import pg
def form():
print """"""
print "Content-Type: text/html\n\n"
print "Searching by using Shot Number"
if __name__ == "__main__":
data = cgi.FieldStorage()
if data:
qtype = data.getfirst('qtype')
qtext = data.getfirst('qtext','')
for qtype in data.getlist('qtype'):
print "You typed in Shot Number:", qtext
#Now, we can get to the database...
username = os.environ.get('USER')
if username == None:
username = 'apache'
db = pg.connect("moncdata", user=username, passwd=None)
query = "select %(qtype)s from shot_descriptions where shot_number=%(qtext)s", qtype, qtext
qresult = db.query(query)
listOfResults = qresult.dictresult()
print """Example of pulling the list of dictionary results apart.
"""
for record in listOfResults:
print ""
for k in record.keys():
print ''
print '| key: | ', k, ' | '
print 'value: | ', record[k], ' | '
print '
'
print '
'
db.close()
else:
print "You have no enter a shot number!"
print "Please type a in shot number in order to perform a search!"
else:
form()
print "