[Tutor] Aschenputtel problem
alan.gauld at freenet.co.uk
Fri Sep 16 00:30:39 CEST 2005
>> [condition(i) and list1.append(i) or list2.append(i) for i in
> Hmm, no, this will always evaluate list2.append(i) because
> the value of list1.append(i) is None. You could use
> [ (condition(i) and list1 or list2).append(i) for i in original ]
Oops! Good point, which emphasises the point about shorter not
necessarily being better!
My personal approach would be two separate comprehensions(*) which
keeps the intent very clear and keeps it short at the expense
of iterating the original list twice.
(*) Or you could use the filter funtion twice if you want to
make the intent even more explicit...
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