[Tutor] checking if a number is evan or odd

[max baseman]

cool thanks
the problem was from a math book imp 1 but i already did the work i  
was just interested in what number had the most steps i could fin  
wanted to get to 1000 imagine how dismayed i was when it crashed at 965

On Sep 3, 2007, at 8:23 PM, Andrew James wrote:

> I'd just go with
>
> if number%2 == 0:
>    number = number/2
>
> Why do you need to convert it to a float?
>
> Off topic:
> Is this a PE problem? I remember doing the same thing.
>
> max baseman wrote:
>> hello just a quick check in, it's about the same program i was  
>> asking  about before ive let it sit for a few days now and i  
>> reached a number  to high to convert to a decimal by adding 0.0
>> here's the program:
>>
>> count=1
>> numstart=268549802
>> number=0
>> high=0
>> a=0
>> while 1==1:
>>      numstart=numstart+1
>>      number=numstart
>>      count=1
>>      while number !=1:
>>          if number/2 == (number+0.0)/2:
>>              number=number/2
>>          else:
>>              number=(number*3)+1
>>          count=count+1
>>      if count > a:
>>          a=count
>>          print numstart,":",count
>>
>>
>> after a few days i got this error:
>>
>> Traceback (most recent call last):
>>    File "homework6high.py", line 11, in <module>
>>      if number/2 == (number+0.0)/2:
>> OverflowError: long int too large to convert to float
>>
>> just wondering if theirs a way to check if a larger number is even  
>> or  odd
>>
>> thanks
>>
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>>
>>