# [Tutor] Looking for duplicates within a list

Alex Hall mehgcap at gmail.com
Fri Jun 11 16:20:20 CEST 2010

```On 6/11/10, Ken G. <beachkid at insightbb.com> wrote:
> I have been working on this problem for several days and I am not making
> any progress.  I have a group of 18 number, in ascending order, within a
> list.  They ranged from 1 to 39.  Some numbers are duplicated as much as
> three times or as few as none.
FYI, Python's "set" data type will let you have a list and never have
a repeat. I know that is not your goal now, but if you want to remove
duplicates, it seems like a good choice.
>
> I started with one list containing the numbers.  For example, they are
> listed as like below:
>
> a = [1, 2, 3, 3, 4]
>
> I started off with using a loop:
>
>     for j in range (0, 5):
>     x = a[0] # for example, 1
>
> How would I compare '1' with 2, 3, 3, 4?
>
> Do I need another duplicated list such as b = a and compare a[0] with
> either b[0], b[1], b[2], b[3], b[4]?
>
> Or do I compare a[0] with a[1], a[2], a[3], a[4]?
A couple points here. First, you will want to make life easier by
saying range(0, len(a)) so that the loop will work no matter the size
of a.
Second, for comparing a list to itself, here is a rather inefficient,
though simple, way:

for i in range(0, len(a)):
x=a[i]
for j in range(0, len(a)):
y=a[j]
if(x==y and i!=j): #match since a[i]==a[j] and i and j are not the
same index of a
>
> In any event, if a number is listed more than once, I would like to know
> how many times, such as 2 or 3 times.  For example, '3' is listed twice
> within a list.
Do not quote me here, but I think sets may be able to tell you that as well.
>
> TIA,
>
> Ken
>
>
>
>
>
>
>
>
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--
Have a great day,
Alex (msg sent from GMail website)
mehgcap at gmail.com; http://www.facebook.com/mehgcap
```

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