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<DIV>Luis and all,</DIV>
<DIV> </DIV>
<DIV>I want to more than matching, I am trying to find all the available combos,
e.g a1 == x1 or a1 == x2 or a1 != x1.</DIV>
<DIV> </DIV>
<DIV>HTH,</DIV>
<DIV>Nathan Pinno </DIV>
<DIV> </DIV>
<DIV>I also noticed you forgot the a[1] == b[1]. (grin) :)</DIV>
<DIV> </DIV>
<DIV>----- Original Message ----- </DIV>
<BLOCKQUOTE
style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=tegmine@gmail.com href="mailto:tegmine@gmail.com">Luis N</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A title=tutor@python.org
href="mailto:tutor@python.org">tutor@python.org</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Wednesday, July 27, 2005 3:01
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [Tutor] How do I go about
this?</DIV>
<DIV><BR></DIV>On 7/27/05, <B class=gmail_sendername>Nathan Pinno</B> <<A
href="mailto:falcon3166@hotmail.com">falcon3166@hotmail.com</A>> wrote:
<DIV><SPAN class=gmail_quote></SPAN>
<BLOCKQUOTE class=gmail_quote
style="PADDING-LEFT: 1ex; MARGIN: 0pt 0pt 0pt 0.8ex; BORDER-LEFT: rgb(204,204,204) 1px solid">
<DIV>Hi all,</DIV>
<DIV> </DIV>
<DIV>How do I go about the following: I want to write a program that will
print two lists one after another, then show all the available possibilities
for matches e.g a0 and x0.</DIV>
<DIV> </DIV>
<DIV>Here is what I have so far:</DIV>
<DIV> </DIV>
<DIV>lista = [x0, x1, x2, x3]<BR>listb = [a0, a1, a2, a3]<BR>print
lista<BR>print listb<BR></DIV>
<DIV>Thanks for the help,</DIV><SPAN class=sg>
<DIV>Nathan Pinno</DIV></SPAN></BLOCKQUOTE>
<DIV><BR><BR>Hi,<BR><BR>Could you give some additional information as to what
you intend to do? If you are strictly matching, by position within the lists,
such that you would print the list elements only if: <BR><BR>for x in
range(min(len(lista),len(listb))):<BR> a =
lista[x]<BR> b = listb[x]<BR> if a ==
b:<BR> print a, b<BR><BR>that is
easy, however, if you want to match more complex patterns, or wish to match
list elements not in the same position then the complexity of the task
increases.</DIV></DIV>
<P>
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