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Thanks, that helps.<br>
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Jorge Godoy wrote:
<blockquote cite="mid87vez3gxjw.fsf@jupiter.g2ctech" type="cite">
<pre wrap="">Johan Geldenhuys <a class="moz-txt-link-rfc2396E" href="mailto:johan@accesstel.co.za"><johan@accesstel.co.za></a> writes:
</pre>
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<pre wrap="">Now that I have the answer (16.800000000000001), How do I round it of to 16.80
? I only need it to be to the closest 1/100.
</pre>
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<pre wrap=""><!---->
</pre>
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<blockquote type="cite">
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<pre wrap="">print "%.2f" % 16.800000000000001
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<pre wrap=""><!---->16.80
</pre>
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<blockquote type="cite">
<blockquote type="cite">
<pre wrap="">a = 16.8000000000001
b = "%.2f" % a
b
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</blockquote>
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<pre wrap=""><!---->'16.80'
</pre>
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<blockquote type="cite">
<blockquote type="cite">
<pre wrap="">float(b)
</pre>
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</blockquote>
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<pre wrap=""><!---->16.800000000000001
</pre>
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<blockquote type="cite">
<blockquote type="cite">
<pre wrap="">str(float(b))
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<pre wrap=""><!---->'16.8'
</pre>
<pre wrap=""><!---->
(The reason for the '000000000001' is because of the numeric base used to
represent data -- binary -- and the numeric base I'm requesting the answer to
be in -- decimal.)
Be seeing you,
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