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<P><SPAN class=717572118-10022007>Hi,</SPAN></P>
<P><SPAN class=717572118-10022007>I read the information at <A
href="http://mail.python.org/mailman/listinfo/tutor">http://mail.python.org/mailman/listinfo/tutor</A> but
am still not sure how to properly send a question. Will I get an email
response without joining the list? </SPAN></P>
<P><SPAN class=717572118-10022007>Thanks for any help.</SPAN></P>
<P><SPAN class=717572118-10022007>Les</SPAN></P>
<P><SPAN class=717572118-10022007></SPAN> </P>
<P><SPAN class=717572118-10022007>I thought when I read the 2002 thread
with the subject (Creating an Identifier or Object Name from a String?),
that I had found a solution to my problem. But, I can't make the concept
work for creating an object identifier. </SPAN></P>
<P><SPAN class=717572118-10022007>THIS WORKS</SPAN></P>
<BLOCKQUOTE dir=ltr style="MARGIN-RIGHT: 0px">
<P><SPAN class=717572118-10022007>class nsf(object):<BR> #
name = ''<BR> def __init__(self,
id):<BR> self.name = id
<BR> <BR># main<BR>Ireland = nsf('Ireland')</SPAN></P></BLOCKQUOTE>
<P><SPAN class=717572118-10022007>BUT - THIS DOESN'T</SPAN></P>
<BLOCKQUOTE dir=ltr style="MARGIN-RIGHT: 0px">
<P><SPAN class=717572118-10022007>class nsf(object):<BR> #
name = ''<BR> def __init__(self,
id):<BR> self.name = id
<BR> <BR># main<BR>cmdstr = "Ireland =
nsf('Ireland')"<BR>eval(cmdstr)</SPAN></P></BLOCKQUOTE>
<P><SPAN class=717572118-10022007>-------------------------</SPAN></P>
<P><SPAN class=717572118-10022007>I get an error saying the following</SPAN></P>
<P><SPAN class=717572118-10022007><FONT
face=Courier> eval(cmdstr)<BR> File
"(string)", line 1<BR> Ireland =
nsf('Ireland')<BR>
^<BR>SyntaxError: invalid
syntax</FONT></SPAN></P>
<P><SPAN class=717572118-10022007>-------------------------</SPAN></P>
<P><SPAN class=717572118-10022007>For reference the thread message that I am
referring to is:</SPAN></P>
<P><SPAN class=717572118-10022007>Gregor Lingl wrote:</SPAN></P>
<BLOCKQUOTE dir=ltr style="MARGIN-RIGHT: 0px">
<P dir=ltr style="MARGIN-RIGHT: 0px"><SPAN class=717572118-10022007>I Tried it
and it worked (?!)<BR><BR>Python 2.2c1 (#27, Dec 14 2001, 13:15:16) [MSC 32
bit (Intel)] on win32<BR>Type "copyright", "credits" or "license" for more
information.<BR>IDLE 0.8 -- press F1 for help<BR>>>><I> class
K:<BR></I>
pass<BR><BR>>>><I> field1 = K()<BR></I>>>><I> field2 =
K()<BR></I>>>><I> field3 = K()<BR></I>>>><I> for ct in
range(1,4):<BR></I>
obj="field"+str(ct)<BR>
objTC=eval(obj)<BR>
objTC.text=['a','b',str(ct)]<BR><BR><BR>>>><I>
field1.text<BR></I>['a', 'b', '1']<BR>>>><I> field2.text<BR></I>['a',
'b', '2']<BR>>>><I> field3.text<BR></I>['a', 'b',
'3']<BR>>>><I><BR></I><BR>Gregor<BR><BR></SPAN><SPAN
class=717572118-10022007></SPAN></P></BLOCKQUOTE>
<P dir=ltr style="MARGIN-RIGHT: 0px"><SPAN class=717572118-10022007>What he did
also works for me. Bur, </SPAN><SPAN class=717572118-10022007>I have tried many
ways to use the same idea for creating an object identifier. I haven't
found a way yet.</SPAN></P>
<P dir=ltr style="MARGIN-RIGHT: 0px"><SPAN
class=717572118-10022007></SPAN> </P>
<P dir=ltr style="MARGIN-RIGHT: 0px"><SPAN class=717572118-10022007> </P>
<DIV dir=ltr style="MARGIN-RIGHT: 0px"></SPAN> </DIV>
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