Here's the better function fixed with a return statement I forgot, but might not be as quick as the pre-built functions already shown:<br><br>def iterToHighNum(increment,high_num):<br>    end_point = 0<br>    a = [i for i in range(0,increment)]<br>
    while (end_point != high_num) == True:<br>        for integer in a:<br>            if integer != high_num:<br>                print "no match, integer = %i" % (integer)<br>                end_point += 1<br>            if end_point == high_num and integer != (high_num - 1):<br>
                print 'match, integer = %i, high_num = %i' % (integer,high_num)<br>                return<br>        <br>        previous_increment = increment<br>        increment += increment<br>        a = [i for i in range(previous_increment,increment)]<br>
<br>#instance<br>increment = 10000<br>high_num = 1000000<br>iterToHighNum(increment,high_num)<br><br><br>