Here's the better function fixed with a return statement I forgot, but might not be as quick as the pre-built functions already shown:<br><br>def iterToHighNum(increment,high_num):<br> end_point = 0<br> a = [i for i in range(0,increment)]<br>
while (end_point != high_num) == True:<br> for integer in a:<br> if integer != high_num:<br> print "no match, integer = %i" % (integer)<br> end_point += 1<br> if end_point == high_num and integer != (high_num - 1):<br>
print 'match, integer = %i, high_num = %i' % (integer,high_num)<br> return<br> <br> previous_increment = increment<br> increment += increment<br> a = [i for i in range(previous_increment,increment)]<br>
<br>#instance<br>increment = 10000<br>high_num = 1000000<br>iterToHighNum(increment,high_num)<br><br><br>