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<div class="moz-cite-prefix">You can break the loop when you get a
positive matches, and add a variable where you can count the
number of positive matches, if it's equal to zero print 'not
found'<br>
<br>
On 24/10/2012 17:43, Saad Javed wrote:<br>
</div>
<blockquote
cite="mid:CAJ5mJ2u1QJW9ATf=_VmXnchKthKHiwhuKLMu24RfVS4AtELKuA@mail.gmail.com"
type="cite">Let me modify this example:
<div><br>
</div>
<div>
<div>a = [['jimmy', '25', 'pancakes'], ['tom', '23',
'brownies'], ['harry', '21', 'cookies']]</div>
<div>
for i in a:</div>
<div> <b>b = i[0]</b></div>
<div> if (i[1] == '25' or i[1] == '26'):</div>
<div> print <b>b</b></div>
<div> else:</div>
<div> print 'Not found'</div>
<div><br>
</div>
<div>This will output:</div>
<div><b>jimmy</b></div>
<div><b>Not found</b></div>
<div><b>Not found</b></div>
<div><b><br>
</b></div>
<div>How do I print positive matches (<b>jimmy</b>) only and not
(<b>Not found</b>). I also want <b>Not found </b>to print
only <i>once </i>if there are no positive matches.</div>
<div><br>
On Wednesday, October 24, 2012, Saad Javed wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">Hi,
<div><br>
</div>
<div>
<div>a = [['jimmy', '25', 'pancakes'], ['tom', '23',
'brownies'], ['harry', '21', 'cookies']]</div>
<div>for i in a:</div>
<div> if (i[1] == '25' or i[1] == '26'):</div>
<div> print 'yes'</div>
<div>else:</div>
<div> print 'Not found'</div>
</div>
<div><br>
</div>
<div>This prints:</div>
<div>yes</div>
<div>not found</div>
<div><br>
</div>
<div>I want it to print "yes" for each positive match but
nothing for a negative match. However if all matches are
negative, I want it to print "Not found" once (That bit
the code already does). I do I get it to print "yes" only
in a mix result situation?</div>
<div><br>
</div>
<div>Saad</div>
</blockquote>
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</blockquote>
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