Mailman 3 November 2007 - Cplusplus-sig

CMake and getting starting with boost.python
by Braddock Gaskill Aug. 5, 2011

Aug. 5, 2011

Yesterday I became a boost.python user, after years of heavy SWIG usage. I would have started using boost.python years ago except for the bjam learning curve. I spent hours TRYING on multiple occasions, but got lost every time trying to get the page one example to build with bjam. Here is how to build the "greet" example with a four line CMake file: cat >>CMakeLists.txt <<EOF LINK_LIBRARIES(boost_python) INCLUDE_DIRECTORIES("/usr/include/python2.5") LINK_DIRECTORIES("/usr/lib/python2.5") # Not needed? ADD_LIBRARY(hello SHARED hello.cpp) EOF You WILL have to `mv libhello.so hello.so` after building. Works for me under Ubuntu Linux 6.10 after apt-get install cmake python2.5-dev boost-python-dev cmake make mv libhello.so hello.so ipython In [1]: import hello In [2]: hello.greet() Out[2]: 'hello, world' Boost.Python has been a joy to learn and use since I got past bjam. I had a moderately large API wrapped in just my first couple hours of learning (less time than I spent messing with bjam). Any additional advice for using CMake to build boost.python? Braddock Gaskill

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How to import a boost::python dll in windows?
by ichijoji Aug. 5, 2011

Aug. 5, 2011

I'm trying to port some research code that uses boost::python to expose a library to python to windows, but I'm having trouble importing the dll into python. I'm compiling using msvc 2005 and using python 2.5, but when I try to import the module I get this: Traceback (most recent call last): File "main.py", line 1, in <module> import object File "c:\code\sge\code\scripts\object.py", line 1, in <module> import sge ImportError: No module named sge My module is named sge and I'm compiling to sge.dll. Is there some obvious reason why python wouldn't be able to find my dll? When I compile on linux into an so this code works fine. -- View this message in context: http://www.nabble.com/How-to-import-a-boost%3A%3Apython-dll-in-windows--tf3… Sent from the Python - c++-sig mailing list archive at Nabble.com.

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Base class defined in other header file not included in bp::bases<>
by Haridev, Meghana Sept. 14, 2008

Sept. 14, 2008

Hi Folks, I'm having some trouble generating boost-python wrapper code using pyplusplus for a derived class which has one of its base classes defined in another file. Simple scenario: mydir/ other.hpp: class baseB{ }; hierarchy.hpp: #include "other.hpp" class baseA{ }; class derivedC: public baseA, public baseB{ }; generate_code.py: import os from pyplusplus import module_builder mb = module_builder.module_builder_t( files=['hierarchy.hpp'] ) mb.build_code_creator( module_name='inherit' ) mb.code_creator.user_defined_directories.append( os.path.abspath('.') ) mb.write_module('boost_hierarchy.cpp') ------------------------------------------------------------------------ ------------------------------------------------- Generated code (boost_hierarchy.cpp) looks like this: // This file has been generated by pyplusplus. #include "boost/python.hpp" #include "hierarchy.hpp" namespace bp = boost::python; BOOST_PYTHON_MODULE(inherit){ bp::class_< baseA >( "baseA" ); bp::class_< derivedC, bp::bases< baseA > >( "derivedC" ); } How can I get pyplusplus to add 'baseB' to bp::bases<> for 'derivedC' class when 'baseB' class is defined in another file (present in the same directory or different directory)? When I move the definition of 'baseB' class to hierarchy.hpp, boost wrapper for 'derivedC' is correctly generated as: bp::class_< derivedC, bp::bases< baseA, baseB > >( "derivedC" ); Thanks, -Meghana.

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Raoul Gough's container suite with svn boost-trunk boost.python?
by John Reid May 18, 2008

May 18, 2008

Has anyone tried using Raoul's container suite with the svn boost-trunk? I'm getting the following error: C:\Dev\ThirdParty\boost\boost-trunk\boost/python/detail/caller.hpp(236) : error C2903: 'extract_return_type' : symbol is neither a class template nor a function template C:\Dev\ThirdParty\boost\boost-trunk\boost/python/detail/caller.hpp(232) : while compiling class template member function 'boost::python::detail::py_func_sig_info boost::python::detail::caller_arity<2>::impl<F,Policies,Sig>::signature(void)' with [ F=boost::python::list (__cdecl *)(std::vector<biopsy::binding_hit> &,boost::python::indexing::slice), Policies=boost::python::indexing::detail::postcall_override<boost::python::indexing::default_container_policies>, Sig=boost::mpl::vector3<boost::python::list,std::vector<biopsy::binding_hit> &,boost::python::indexing::slice> ] So the problem seems to be there is no extract_return_type in boost::python::indexing::detail::postcall_override<boost::python::indexing::default_container_policies> If I remember correctly, I've installed Roman's version by copying it into boost/python/suite/indexing John.

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'iteritems', 'iterkeys' and 'itervalues' in dict
by Nindi Singh April 11, 2008

April 11, 2008

Apolgies for not putting the subject line in my last email. In the Boost.Python dict class there are methods 'iteritems', 'iterkeys' and 'itervalues' all returning objects. How exactly are you supposed to use these objects (iterators) ? ___________________________________________________________ Inbox full of spam? Get leading spam protection and 1GB storage with All New Yahoo! Mail. http://uk.docs.yahoo.com/nowyoucan.html

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Custom smart pointer with same behaviour as shared_ptr
by Francis Moreau Jan. 23, 2008

Jan. 23, 2008

Hi, I am passing Python objects to C++ through a shared_ptr smart pointer and it's work well. However I need to have the same behaviour as shared_ptr but with my own version of smart pointer. I try to register and expose my custom smart pointer but I have this compilation error: boost/python/pointee.hpp(28) : error C2039: 'element_type': is not a member of 'CountedObjPtr<T>' with [ T=PyCallEngineState ] boost/python/pointee.hpp(38) : see reference to class template instantiation 'boost::python::detail::pointee_impl<false>::apply<T>' being compiled with [ T=CountedObjPtr<PyCallEngineState> ] boost/python/register_ptr_to_python.hpp(17) : see reference to class template instantiation 'boost::python::pointee<T>' being compiled with [ T=CountedObjPtr<PyCallEngineState> ] PythonModules.cpp(113) : see reference to function template instantiation 'void boost::python::register_ptr_to_python<CountedObjPtr<T>>(void)'being compiled with [ T=PyCallEngineState ] Here is the content of the from_python file for my smart pointer: template <class T> struct CountedObjPtr_from_python { CountedObjPtr_from_python() { converter::registry::insert(&convertible, &construct, type_id<CountedObjPtr<T> >()); } static void* convertible(PyObject* p) { if (p == Py_None) { return p; } return converter::get_lvalue_from_python( p, python::converter::registered<T>::converters); } static void construct(PyObject* source, python::converter::rvalue_from_python_stage1_data* data) { void* const storage = ((python::converter::rvalue_from_python_storage<CountedObjPtr<T> >*)data)->storage.bytes; // Deal with the "None" case. if (data->convertible == source) { new (storage) CountedObjPtr<T>(); } else { new (storage) CountedObjPtr<T>(static_cast<T*>(data->convertible)); } data->convertible = storage; } }; And here is the code where I register the smart pointer: namespace boost{ namespace python{ template <class T> struct pointee< CountedObjPtr<const T> > { typedef T type; }; template <class T> inline T* get_pointer(CountedObjPtr<const T> const& p) { return const_cast<T*>(p.get()); } }} template <typename T> void register_CountedObjPtr_conversions() { boost::python::converter::registry::insert( &CountedObjPtr_from_python<T>::convertible, &CountedObjPtr_from_python<T>::construct, boost::python::type_id<CountedObjPtr<T> >()); } BOOST_PYTHON_MODULE(CallEngineExtending) { python::class_<PyCallEngineState, PyCallEngineState_Wrapped, boost::noncopyable>("PyCallEngineState") ; //register_ptr_to_python<boost::shared_ptr<PyCallEngineState> >(); python::register_ptr_to_python<CountedObjPtr<PyCallEngineState> >(); register_CountedObjPtr_conversions<PyCallEngineState>(); } Is anyone knows what is missing or wrong with this code? Also, I am not sure this code manages the ref counting properly since there is no call to borrowed or something like this? Any help would be appreciated, Francis

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std::tr1::shared_ptr as boost::shared_ptr
by Piotr Jaroszynski Jan. 16, 2008

Jan. 16, 2008

Hello, I am exposing a C++ app, which makes heavy use of tr1::shared_ptr, which seems to be exactly(?) the same as boost::shared_ptr. I have managed to make most of the stuff work just as it would be boost::shared_ptr ( additionally adding support for shared_ptr<const T> - thanks to [1] ): namespace my_app_namespace { //Make Boost.Python work with std::tr1::shared_ptr<> template<typename T_> inline T_ * get_pointer(std::tr1::shared_ptr<T_> const & p) { return p.get(); } //Make Boost.Python work with std::tr1::shared_ptr<const> template<typename T_> inline T_ * get_pointer(std::tr1::shared_ptr<const T_> const & p) { return const_cast<T_*>(p.get()); } } namespace boost { namespace python { //Make Boost.Python work with std::tr1::shared_ptr<> template<typename T_> struct pointee<std::tr1::shared_ptr<T_> > { typedef T_ type; }; //Make Boost.Python work with std::tr1::shared_ptr<const> template<typename T_> struct pointee<std::tr1::shared_ptr<const T_> > { typedef T_ type; }; } } What is still not working is the implicit conversion of Foo and Derived for functions taking std::tr1::shared_ptr<Foo>. With boost::shared_ptr it just works when you add the bp::bases<Foo> to the Derived: func(boost::shared_ptr<Foo>) ... bp::class_<Foo> ... bp::class_<Derived, bp::bases<Foo> > ... and func can take both Foo and Derived. But with std::tr1::shared_ptr I have to use: func(std::tr1::shared_ptr<Foo>) ... bp::class_<Foo, std::tr1::shared_ptr<Foo> > ... bp::class_<Derived, std::tr1::shared_ptr<Derived>, bp::bases<Foo> > ... bp::implicitly_convertible<std::tr1::shared_ptr<Foo>, std::tr1::shared_ptr<Derived> >(); How can I make it working just as with boost::shared_ptr? Btw. I have seen [2] already, but it doesn't seem to cover that. [1] - http://language-binding.net/pyplusplus/troubleshooting_guide/shared_ptr/sha… [2] - http://language-binding.net/pyplusplus/troubleshooting_guide/smart_ptrs/sma… -- Best Regards, Piotr Jaroszynski

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To Spicy For Py++ [was: A wrapped class contains another wrapped class. Hilarity ensues.]
by Matthew Scouten Dec. 4, 2007

Dec. 4, 2007

On Nov 27, 2007 12:07 PM, Roman Yakovenko <roman.yakovenko(a)gmail.com> wrote: > On Nov 27, 2007 7:59 PM, Matthew Scouten <matthew.scouten(a)gmail.com> > wrote: > > AH! yes that worked. Thank you so much. It seems the real WTF here was > that > > it seemed to work fine when the foo was instantiated directly from > python. > > Because that seemed to work, I thought I was doing everything right > until I > > get further into wrapping my library. > > > > Please ignore my earlier begging email. I was way the heck down the > wrong > > path, looking for the wrong solutions, and getting very frustrated. > > I suggest you to try Py++ ( http://www.language-binding.net/ ). It > could help you to avoid such things. > > It has simple, but still useful GUI: > > http://language-binding.net/pyplusplus/documentation/tutorials/pyplusplus_g… We did try that. GCC-XML chokes on our library code. It was originally written for C, and later ported to C++. Along the way it picked up some crazy preprocessor and template hacks and even some meta-template programming. Granted most of this stuff is not the part we need to wrap, but it is not easily separable. On top of all that, it was written with msvc8 in mind, not GCC. Even with with options set to emulate msvc8, GCC-XML generates hundreds of error messages the last of which is "internal compiler error". It works fine on other code, and our library compiles just fine on msvc8. We thought it would be faster to just soldier on in raw Boost.Python.

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Wrapping an enum like class that is not an enum
by Matthew Scouten Dec. 3, 2007

Dec. 3, 2007

I (a BP newbie) could use some advice on how th wrap something odd. The library I am using has something called an AEnum. It is a type of enum like class. It is guaranteed to behave exactly like an enum, except that it has some extra properties. There is an int, a string and a symbol associated with each value. In spite of that, the sizeof(AEnum_blah) == sizeof(int) , Guaranteed an AEnum is castable to and from an int and the bits of the AEnum are identical to the bits of the int it casts to. I can't wrap it as a class because it is generated by crazy macros and meta-template programming (And besides, I don't understand it...) So, I thought, If this thing is Guaranteed to be just like an enum in everyway that matters, why not pretend that it IS an enum and wrap it like one? So I used the "enum_<>()" Well that works just great when passing to or returning from functions. Except, if it is the member of a class... >>> from MantiCore import * >>> o = Order() >>> o.order_status Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: cannot create weak reference to 'MantiCore.AEnum_OrderStatusCodes' object I can get around this by exporting it as a property of the class rather than a data member, but there are a lot of them. So, Anyone have a better way to do this?

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Re: [C++-sig] Embedding and calling extended python commands
by Satyajit Sarangi Nov. 30, 2007

Nov. 30, 2007

Hi Stefan, The errors which I get are as follows: Python File 1: import smallPython a = smallPython a.greet() a.square(100) Error: C:\Python25>testpy test.py running file test.py... y:\private\my documents\ssarangi\my documents\visual studio 2005\projects\smallpython\smallpython\main.cpp(166): Python Error detected in function 'int __cdecl main(int,char **)' Traceback (most recent call last): File "test.py", line 1, in <module> import smallPython ImportError: __import__ not found 1 error detected. However, I can import the smallPython module directly into the python interpreter... Seems like I am missing something and also it shows me an error for the cpp file when I have the smallPython.pyd and smallPython.lib in the python root directory. The cpp file is the same as the example getting_started_1.cpp Cpp File: #include <boost/python/module.hpp> #include <boost/python/def.hpp> #include <string> namespace { // Avoid cluttering the global namespace. // A couple of simple C++ functions that we want to expose to Python. std::string greet() { return "hello, world"; } int square(int number) { return number * number; } } namespace python = boost::python; // Python requires an exported function called init<module-name> in every // extension module. This is where we build the module contents. BOOST_PYTHON_MODULE(smallPython) { // Add regular functions to the module. python::def("greet", greet); python::def("square", square); } Thanks a lot for the help Satyajit

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