Dusty Leary <dleary@gmail.com> writes:
full source code: ================================================ #define BOOST_PYTHON_STATIC_LIB
#include <boost/python.hpp> using namespace boost::python;
struct X { std::string v; X(const std::string& s) : v(s) {} operator char*() const { return (char*)v.c_str(); } };
void test_x(X& x) { char* x_string = x; printf("test_x: %s\n", x_string); }
void test_string(char* s) { printf("test_string: %s\n", s); }
Oh! char* is not a C++ string, and there's no built-in converter for that. I note that you're casting away the const-ness of v.c_str() above; that's very bad juju. If you make char* into char const* everywhere, your example should work. Alternatively, you can also register a custom from_python converter for char*... but I recommend against it.
BOOST_PYTHON_MODULE(test_string) { class_<X>("X", init<const std::string&>()); def("test_x", test_x); def("test_string", test_string); implicitly_convertible<X, char*>(); } ================================================
interpreter:
import test_string x = test_string.X("foo") test_string.test_x(x) test_x: foo test_string.test_string("blah") test_string: blah test_string.test_string(x) Traceback (most recent call last): File "<stdin>", line 1, in ? Boost.Python.ArgumentError: Python argument types in test_string.test_string(X) did not match C++ signature: test_string(char *)
-- Dave Abrahams Boost Consulting http://www.boost-consulting.com