That worked wonderfully, thank you. I did have to make a small change to accomadate VC++ 6: module_namespace["DerivedClass"] changed to module_namespace.get("DerivedClass")
I will suppose you have access to the module namespace containing the derived class. I'll call this "module_namespace". So, you can retrieve the class using Boost.Python very simply :
boost::python::object cls = module_namespace["DerivedClass"]
And now, you can create the object with :
boost::python::object obj = cls();
And to get a pointer to the underlying C++ object :
MyClass* cpp_obj = extract<MyClass*>(obj);
It should work ...
Pierre
Peter a écrit :
Another question, and I really hope this doesn't get emailed four idnetical times like my last question. My sincere apologies in advance if it does.
I have a C++ class with a virtual function that I want overridden in Python. I expose it to Python in the normal way:
class_<MyClass>("CPP_Class", no_init) .def("vfunc", &MyClass::func);
And in Python the user derives from this class overrides the virtual method, e.g.:
class DerivedClass(CPP_Class): def vfunc(self): #do stuff in Python
I want to create an instance of "DerivedClass" from C++ and assign it to the base class ptr and then call the overridden Python function via the virtual fn defined in the C++ base class. So my question is; how do I, from C++, create this instance of DerivedClass (assuming I know that the user called it DerivedClass)?
Thank you very much for any help, Peter
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