I have a python class that wraps a boost.python object. I am using a boost.python library function that requires the raw boost.python object. I want to be able to pass the python object to the boost api function. Is there a hook available on the python side that instructs boost to perform a conversion? Hypothetically, it would be something like this: class EggWrapper(object): def __init__(self, egg): object.__setattr__(self, '_egg', egg) def __getattribute__(self, name): egg = object.__getattribute__(self, '_egg') if name=='_egg': return egg if name in EggWrapper.__dict__: return object.__getattribute__(self, name) return getattr(egg, name) def __setattr__(self, name, value): egg = object.__getattribute__(self, '_egg') setattr(egg, name, value) def magic_boost_conversion_unicorn_hook(self): 'this is automatically called by boost to convert arguments' egg = object.__getattribute__(self, '_egg') return egg import myboostlib egg = EggWrapper(myboostlib.getEgg()) myboostlib.spam(egg) Where the signature for spam is: spam(class boost::python::api::object) And myboostlib.getEgg() returns a boost::python::api::object - I do not have the ability to modify the library or any C/C++ code, the solution must be entirely on the python side. - I can't change the calling convention. The wrapped object must be used (i.e. I can't just say myboostlib.spam(egg._egg), though that is the desired result). So the solution should be incorporated into the EggWrapper class. - I'm only interested in solutions that reflect expert knowledge of Boost.Python, since I believe I have already considered all the trivial solutions. So my question is, does magic_boost_conversion_unicorn_hook() exist, and if so, how is it spelled? Thanks, Ken