That worked wonderfully, thank you. I did have to make a small change to accomadate VC++ 6: module_namespace["DerivedClass"] changed to module_namespace.get("DerivedClass")

I will suppose you have access to the module namespace containing the derived class. I'll call this "module_namespace". So, you can retrieve the class using Boost.Python very simply :

boost::python::object cls = module_namespace["DerivedClass"]

And now, you can create the object with :

boost::python::object obj = cls();

And to get a pointer to the underlying C++ object :

MyClass* cpp_obj = extract<MyClass*>(obj);

It should work ...

Pierre

Peter a écrit :

...

Another question, and I really hope this doesn't get emailed four idnetical times like my last question. My sincere apologies in advance if it does.

I have a C++ class with a virtual function that I want overridden in Python. I expose it to Python in the normal way:

class_<MyClass>("CPP_Class", no_init) .def("vfunc", &MyClass::func);

And in Python the user derives from this class overrides the virtual method, e.g.:

class DerivedClass(CPP_Class): def vfunc(self): #do stuff in Python

I want to create an instance of "DerivedClass" from C++ and assign it to the base class ptr and then call the overridden Python function via the virtual fn defined in the C++ base class. So my question is; how do I, from C++, create this instance of DerivedClass (assuming I know that the user called it DerivedClass)?

Thank you very much for any help, Peter

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