Hi Team, I have noticed if our regex sometimes does not give a result and on that time regex took more time in returning response (empty response). My Question is can we set a timeout parameter (in seconds/millisecond) with re.find or anywhere in code to avoid CPU consumption if regex takes more time in execution. Below is the example, which take more time in execution: (in this case can we set timeout to kill the execution to avoid CPU consumption) regex = r'data-stid="section-room-list"[\s\S]*?>\s*([\s\S]*?)\s*' \ r'(?:class\s*=\s*"\s*sticky-book-now\s*"|</ul>\s*</section>|id\s*=\s*"Location")' rooms_blocks_to_be_replace = re.findall(regex, html_template) Please help me, I will be very thankful for this. Shahiquzzama Mob No: +919650823727
