[docs] [issue13899] re pattern r"[\A]" should work like "A" but matches nothing. Ditto B and Z.

Feb. 3, 2012

      Matthew Barnett <python@mrabarnett.plus.com> added the comment:

This should answer that question:
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re.findall(r"[\A\C]", r"\AC")
['C']
regex.findall(r"[\A\C]", r"\AC")
['A', 'C']
The behaviour of regex is intended to match that of re for backwards compatibility.

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<http://bugs.python.org/issue13899>
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