[docs] [issue11681] -b option undocumented

Nick Coghlan added the comment:

Right, the lack of transitivity comes from the fact that:

>>> u"3" == str(3) True

Is really shorthand for:

>>> u"3" == str(3).decode("ascii") True

However, the implicit decoding only triggers for *exactly* bytes instances, so in the bytearray case it needs to be explicit:

>>> u"3" == bytearray(b"3").decode("ascii") True

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