[docs] [issue40579] Second argument to iterator.next not described

May 9, 2020

      Raymond Hettinger <raymond.hettinger@gmail.com> added the comment:

The next() function has a different signature than the __next__() method.  The former takes one or two arguments.  That latter only takes one.

    >>> it = iter('abcde')
    >>> next(it)
    'a'
    >>> next(it, 'default')
    'b'
    >>> it.__next__()
    'c'
    >>> it.__next__('default')
    Traceback (most recent call last):
      File "<pyshell#4>", line 1, in <module>
        it.__next__('default')
    TypeError: expected 0 arguments, got 1

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nosy: +rhettinger

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