[docs] [issue16011] "in" should be consistent with return value of __contains__

Eric Lafontaine added the comment: oh, I've got what you meant! Proposed change : For user-defined classes which define the __contains__() method, the in operator will convert to False "x in y" if y.__contains__(x) return False, 0 or None. Otherwise, the in operator will return True for any other value being returned by y.__contains__(x). Would that make more sense? Regards, Eric Lafontaine ---------- _______________________________________ Python tracker <report@bugs.python.org> <http://bugs.python.org/issue16011> _______________________________________