July 5, 2012
4:47 p.m.
Daniel Urban <urban.dani+py@gmail.com> added the comment: __prepare__ is not implicitly a staticmethod, and it is called exactly as documented (also in types.prepare_class). There is no implicit first argument because the method is called on the (meta)class object. ---------- _______________________________________ Python tracker <report@bugs.python.org> <http://bugs.python.org/issue15243> _______________________________________