July 23, 2015
11:21 a.m.
New submission from Antoine Pietri: In the new types.coroutines() documentation, it is not clearly stated whether this function is idempotent or not: what happens when it is called on a function that is already a native coroutine? ---------- assignee: docs@python components: Documentation messages: 247184 nosy: docs@python, seirl priority: normal severity: normal status: open title: types.coroutines() idempotence documentation versions: Python 3.5 _______________________________________ Python tracker <report@bugs.python.org> <http://bugs.python.org/issue24692> _______________________________________