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Hello. So I managed to fix it, but I think I had an experience with a bug... It seems that a slice of a numpy array gave me some trouble. Only after redefining the slice as a numpy array would the code run as normal again. In other words: NOT working: zk = np.array(list1) zk2 = zk[a:b] Working: zk = np.array(list1) zk2 = np.array(zk[a:b]) I also checked and it does say that a slice of an array should be an array: in: zk[a:b] out: arra(list1[a:b]) The problem was that it would link the two variables zk and zk2 together: zk = array1 zk2 = array1[a:b] When i changed zk2[0] to a different value, the corresponding element, zk[a], also changes. So for example: zk = np.array([1,2,3,4,5]) zk2 = np.array(zk[1:4]) in: print(zk) print(zk2) out: array([1,2,3,4,5]) array([2,3,4]) in: zk_2[0] = 0 print(zk) print(zk2) out: array([1,0,3,4,5]) array([0,3,4]) Additional information: - zk is read in from a .csv file using pandas. - I am using Spyder/Anaconda - When i change a value of zk_2 in the command window, zk remains the same Allright, thought I would let someone know. Let me know if you need additional information. Kind regards, Leon
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Leon, The documentation at : https://numpy.org/doc/stable/user/basics.indexing.html?highlight=slice does say that slicing creates a view into the original, and not a new object. So it isn't a bug - it is entirely expected behaviour To Quote : NumPy slicing creates a view <https://numpy.org/doc/stable/glossary.html#term-view> instead of a copy as in the case ofbuilt-in Python sequences such as string, tuple and list.Care must be taken when extractinga small portion from a large array which becomes useless after theextraction, because the small portion extracted contains a referenceto the large original array whose memory will not be released untilall arrays derived from it are garbage-collected. In such cases anexplicit copy() is recommended. ------ Original Message ------ From: "Leon fevang-gunn" <leon.fevanggunn@gmail.com> To: docs@python.org Sent: Monday, 18 Jul, 22 At 15:59 Subject: [docs] Suspected bug Hello. So I managed to fix it, but I think I had an experience with a bug... It seems that a slice of a numpy array gave me some trouble. Only after redefining the slice as a numpy array would the code run as normal again. In other words: NOT working: zk = np.array(list1) zk2 = zk[a:b] Working: zk = np.array(list1) zk2 = np.array(zk[a:b]) I also checked and it does say that a slice of an array should be an array: in: zk[a:b] out: arra(list1[a:b]) The problem was that it would link the two variables zk and zk2 together: zk = array1 zk2 = array1[a:b] When i changed zk2[0] to a different value, the corresponding element, zk[a], also changes. So for example: zk = np.array([1,2,3,4,5]) zk2 = np.array(zk[1:4]) in: print(zk) print(zk2) out: array([1,2,3,4,5]) array([2,3,4]) in: zk_2[0] = 0 print(zk) print(zk2) out: array([1,0,3,4,5]) array([0,3,4]) Additional information: - zk is read in from a .csv file using pandas. - I am using Spyder/Anaconda - When i change a value of zk_2 in the command window, zk remains the same Allright, thought I would let someone know. Let me know if you need additional information. Kind regards, Leon _______________________________________________ docs mailing list -- docs@python.org To unsubscribe send an email to docs-leave@python.org https://mail.python.org/mailman3/lists/docs.python.org/ <https://mail.python.org/mailman3/lists/docs.python.org/> Member address: anthony.flury@btinternet.com -- <br>Anthony Flury<br>anthony.flury@btinternet.com
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Leon, The documentation at : https://numpy.org/doc/stable/user/basics.indexing.html?highlight=slice does say that slicing creates a view into the original, and not a new object. So it isn't a bug - it is entirely expected behaviour To Quote : NumPy slicing creates a view <https://numpy.org/doc/stable/glossary.html#term-view> instead of a copy as in the case ofbuilt-in Python sequences such as string, tuple and list.Care must be taken when extractinga small portion from a large array which becomes useless after theextraction, because the small portion extracted contains a referenceto the large original array whose memory will not be released untilall arrays derived from it are garbage-collected. In such cases anexplicit copy() is recommended. ------ Original Message ------ From: "Leon fevang-gunn" <leon.fevanggunn@gmail.com> To: docs@python.org Sent: Monday, 18 Jul, 22 At 15:59 Subject: [docs] Suspected bug Hello. So I managed to fix it, but I think I had an experience with a bug... It seems that a slice of a numpy array gave me some trouble. Only after redefining the slice as a numpy array would the code run as normal again. In other words: NOT working: zk = np.array(list1) zk2 = zk[a:b] Working: zk = np.array(list1) zk2 = np.array(zk[a:b]) I also checked and it does say that a slice of an array should be an array: in: zk[a:b] out: arra(list1[a:b]) The problem was that it would link the two variables zk and zk2 together: zk = array1 zk2 = array1[a:b] When i changed zk2[0] to a different value, the corresponding element, zk[a], also changes. So for example: zk = np.array([1,2,3,4,5]) zk2 = np.array(zk[1:4]) in: print(zk) print(zk2) out: array([1,2,3,4,5]) array([2,3,4]) in: zk_2[0] = 0 print(zk) print(zk2) out: array([1,0,3,4,5]) array([0,3,4]) Additional information: - zk is read in from a .csv file using pandas. - I am using Spyder/Anaconda - When i change a value of zk_2 in the command window, zk remains the same Allright, thought I would let someone know. Let me know if you need additional information. Kind regards, Leon _______________________________________________ docs mailing list -- docs@python.org To unsubscribe send an email to docs-leave@python.org https://mail.python.org/mailman3/lists/docs.python.org/ <https://mail.python.org/mailman3/lists/docs.python.org/> Member address: anthony.flury@btinternet.com -- <br>Anthony Flury<br>anthony.flury@btinternet.com
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anthony.flury
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Leon fevang-gunn