[issue13899] re pattern r"[\A]" should work like "A" but matches nothing. Ditto B and Z.
Feb. 3, 2012
9:08 p.m.
Matthew Barnett <python@mrabarnett.plus.com> added the comment: This should answer that question:
re.findall(r"[\A\C]", r"\AC") ['C'] regex.findall(r"[\A\C]", r"\AC") ['A', 'C']
The behaviour of regex is intended to match that of re for backwards compatibility. ---------- _______________________________________ Python tracker <report@bugs.python.org> <http://bugs.python.org/issue13899> _______________________________________
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Matthew Barnett