-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Am 27.06.2013 02:25, schrieb Alexander Heger:

http://docs.python.org/3.3/library/re.html

6.2.1. Regular Expression Syntax

(way down)

it says:

\number Matches the contents of the group of the same number. Groups are numbered starting from 1. For example, (.+) \1 matches 'the the' or '55 55', but not 'the end' (note the space after the group). This special sequence can only be used to match one of the first 99 groups. If the first digit of number is 0, or number is 3 octal digits long, it will not be interpreted as a group match, but as the character with octal value number. Inside the '[' and ']' of a character class, all numeric escapes are treated as characters.

The example of what does not work is wrong

In [1]: import re

In [2]: re.findall(r'(.+) \1','the end') Out[2]: ['e']

It probably should be

\number Matches the contents of the group of the same number. Groups are numbered starting from 1. For example, (.+) \1 matches 'the the' or '55 55', but not 'thethe' (note the space after the group). This special sequence can only be used to match one of the first 99 groups. If the first digit of number is 0, or number is 3 octal digits long, it will not be interpreted as a group match, but as the character with octal value number. Inside the '[' and ']' of a character class, all numeric escapes are treated as characters.

Hi Alexander, thanks for the report; this is now fixed and should be online soon. cheers, Georg -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.21 (GNU/Linux) iEYEARECAAYFAlJRQmwACgkQN9GcIYhpnLALdgCdG16SAUH9eBZWjXNnl6yWGkeW 0bcAnRXELerjnSVWaAO2yx4F/iWZPqLR =c8Xy -----END PGP SIGNATURE-----