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I have found what seems to be a little bug in the datetime package in Python 3.9.13. I was working with `datetime.datetime.now().microsecond`, which should return the microsecond of the current time - it does so, but the value is returned as an integer. This means that leading zeros of the value will be cropped, and the isolated value of the `.microsecond` will be flawed. This is code in use. Here the full timestamp from `datetime.datetime.now().microsecond` is printed together with the re-combined timestamp from `datetime.datetime.now().year`, `.month`, `.day`, `.hour`, `.minute`, `.second` and `.microsecond`: ``` max_iter = 10 i = 0 temp_sec = None while True: time_now = datetime.datetime.now() sec = time_now.second if sec % 1 == 0 and sec != temp_sec: i += 1 print(time_now.strftime("%Y-%m-%d %H:%M:%S.%f")) print(time_now.year, time_now.month, time_now.day, '', (str(time_now.hour)+':'+str(time_now.minute)+ ':'+str(time_now.second)+'.' +str(time_now.microsecond)) ) print() temp_sec = sec if i > max_iter: break time.sleep(0.01) ``` ``` Output:
This seems like a bug to me.
Best regards
- August Birk
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Hi,
I was working with `datetime.datetime.now().microsecond`, which should return the microsecond of the current time - it does so, but the value is returned as an integer. This means that leading zeros of the value will be cropped, and the isolated value of the `.microsecond` will be flawed.
Do you mean that 1 microsecond is not equal to 01 microsecond? -- [Julien Palard](https://mdk.fr)
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Hi,
I was working with `datetime.datetime.now().microsecond`, which should return the microsecond of the current time - it does so, but the value is returned as an integer. This means that leading zeros of the value will be cropped, and the isolated value of the `.microsecond` will be flawed.
Do you mean that 1 microsecond is not equal to 01 microsecond? -- [Julien Palard](https://mdk.fr)
participants (2)
-
August Birk
-
Julien Palard