New submission from Lucca Ruhland <lucca.ruhland@gmail.com>: When parsing arguments with a namespace object, the subparser are behaving different than the main parser, although this is not stated in the documentation. Each attribute which is not already part of the namespace, should be saved into the namespace object. Therefore any already existing namespace attribute should overwrite the default value of any argument which is not explicitly set. While this is true for the parent parser, it does not work for the subparser. Here is a small example code: ------------------------------------------------------------------------ import argparse parser = argparse.ArgumentParser() parser.add_argument('--root', type=str, default='.') subparsers = parser.add_subparsers() subparser = subparsers.add_parser('subp') subparser.add_argument('--subroot', type=str, default='./subdir') our_args = argparse.Namespace(root="./config_root", subroot="./config_subdir") argv = ['subp'] args = parser.parse_args(argv, namespace=our_args) print(args) ------------------------------------------------------------------------

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Expected: Namespace(root='./config_root', subroot='./config_subdir') Output: Namespace(root='./config_root', subroot='./subdir')

When calling the subparser, the namespace attribute is overwritten by the default value. ---------- assignee: docs@python components: Documentation messages: 376183 nosy: docs@python, lucca.ruhland priority: normal severity: normal status: open title: argparse: unexpected subparser behaviour on parse_args with namespace option type: behavior versions: Python 3.8 _______________________________________ Python tracker <report@bugs.python.org> <https://bugs.python.org/issue41684> _______________________________________