Hi,

`lead.cell_hamiltonian()` gives 32000. The thickness of my slab is 50. Is this something not possible to calculate?

Best!

Chong Wang

From: Joseph Weston <joseph.weston08@gmail.com>
Sent: Wednesday, May 11, 2016 9:02 PM
To: Chong Wang
Cc: kwant-discuss@kwant-project.org
Subject: Re: [Kwant] scatter without a center area

Hi again,

I have (stupidly) tried to copy two slices in central region (one for each lead). After 3 hours, the memory blows up. My workstation has 128Gb DDR4 memory. (kwant is compiled against mumps 5.0.1 and multithreading is working)

This is not probably not normal. I don't think reducing the problem size by 50% is

going to help you; how many degrees of freedom do you have in 1 lead slice?!

i.e. what is the dimension of the matrix returned by `lead.cell_hamiltonian()`?

Joe