Yes, that is correct. The equation that you quoted is indeed the probability current

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On Mon, Jan 23, 2017 at 10:00 AM, Anton Akhmerov <anton.akhmerov+kd@gmail.com> wrote:

> Sorry I made a mistake in the units of 'I'. Isn't 'I' here the probability current and not the charge current? We would just have to multiply 'I' by e to get the charge current, right?

Yes, that is correct. The equation that you quoted is indeed the

probability current.