[Kwant] Re: Discretizing continuous Hamiltonians

Dear Adel, Thank you very much for your kind remind. Khani On Tue, Dec 8, 2020 at 4:11 AM Abbout Adel wrote:

Dear Hosein,

To my knowledge, Kwant "discretize" works only for square lattices. In the version 1.4, it was extended to rectangular ones. So, you can not use it for graphene for example.

I hope this helps, Adel

On Mon, Dec 7, 2020 at 7:44 PM Khani Hosein wrote:

...

Dear all, I want to discretize the continuous Hamiltonian using kwant.continuum.discretize, but I have problems in inputing my hamiltonian. In the example, we only have elements in H(0,0),H(0,1),H(1,0),H(1,1),H(2,2),H(2,3),H(3,2),H(3,3), but in my system (for example, bilayer graphene) I have elements in H(0,2),H(1,3),H(2,0),H(3,1). How to input my hamiltonian into it.

For example, hamiltonian = """ + M * kron(sigma_z, sigma_0) +A * k_x * kron(sigma_0, sigma_x) +A * k_y * kron(sigma_0, sigma_y)+ Tc*[[0, 0, 1, 0], [0, 0, 0, 1],[1, 0, 0, 0] ],[0, 1, 0, 0]] """ The term Tc*[[0, 0, 1, 0], [0, 0, 0, 1],[1, 0, 0, 0] ],[0, 1, 0, 0]] will cause errors. Thank you very much. Khani Hosein

-- Abbout Adel