Hi, this is a follow up question to a previous (hijacked?) thread. For completeness I will provide all details, so that no cross referencing is necessary. I want to compute the electrical conductance of a N-S interface embedded on a hexagonal lattice. The final result should look something like the picture I have attached. The BdG equation is specified in the .pdf. At the moment I have both particle-hole and spin-up/down degrees of freedom, because later I want to add magnetic fields and such. To attack the problem I have tried to follow the steps outlined in tutorial 2.6 with the addition that I use 4 orbitals and a hexagonal lattice. The conductance should still be given as N - R_{ee,\uparrow} - R_{ee,\downarrow} + R_{he,\uparrow} + R_{he,\downarrow}. Here e, h, \uparrow, and \downarrow refers to electron, hole, spin-up, and spin-down respectively. In the documentation it says that smatrix.transmission((i, a), (j, b)) gives the transmission from block b of lead j to block a of lead i. I would therefore expect smatrix.transmission((0, 2), (0, 0)) to give me the transmission of an incident electron of spin up in lead 0 to a reflected hole of spin up in lead 0. With this in mind I thought I could write data.append(smatrix.submatrix((0, 0), (0, 0)).shape[0]- smatrix.transmission((0, 0), (0, 0)) - smatrix.transmission((0, 1), (0, 0)) + smatrix.transmission((0, 2), (0, 0)) + smatrix.transmission((0,3), (0, 0))) to compute the conductance. However, doing this gives me an out of bounds error. As a last resort I tried to write data.append(smatrix.submatrix((0, 0), (0, 0)).shape[0] - smatrix.transmission((0, 0), (0, 0)) + smatrix.transmission((0, 1), (0, 0))) as given in the tutorial 2.6. However, this gives me that the conductance is zero. My question is then, how do I correctly interpret the smatrix.transmission function in my example so that I can compute the correct conductance? I have attached my code in the .txt file. Best, Martin
